5[3t-(2-t)]=3(2t-1)

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Solution for 5[3t-(2-t)]=3(2t-1) equation:


Simplifying
5[3t + -1(2 + -1t)] = 3(2t + -1)
5[3t + (2 * -1 + -1t * -1)] = 3(2t + -1)
5[3t + (-2 + 1t)] = 3(2t + -1)

Reorder the terms:
5[-2 + 3t + 1t] = 3(2t + -1)

Combine like terms: 3t + 1t = 4t
5[-2 + 4t] = 3(2t + -1)
[-2 * 5 + 4t * 5] = 3(2t + -1)
[-10 + 20t] = 3(2t + -1)

Reorder the terms:
-10 + 20t = 3(-1 + 2t)
-10 + 20t = (-1 * 3 + 2t * 3)
-10 + 20t = (-3 + 6t)

Solving
-10 + 20t = -3 + 6t

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-6t' to each side of the equation.
-10 + 20t + -6t = -3 + 6t + -6t

Combine like terms: 20t + -6t = 14t
-10 + 14t = -3 + 6t + -6t

Combine like terms: 6t + -6t = 0
-10 + 14t = -3 + 0
-10 + 14t = -3

Add '10' to each side of the equation.
-10 + 10 + 14t = -3 + 10

Combine like terms: -10 + 10 = 0
0 + 14t = -3 + 10
14t = -3 + 10

Combine like terms: -3 + 10 = 7
14t = 7

Divide each side by '14'.
t = 0.5

Simplifying
t = 0.5

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